Answer
$${\left. {\frac{{dw}}{{ds}}} \right|_{s = 0}} = \sqrt 3 $$
Work Step by Step
$$\eqalign{
& w = \sin \left( {\sqrt r - 2} \right){\text{ and }}r = 8\sin \left( {s + \pi /6} \right) \cr
& {\text{Then}} \cr
& w = \sin \left( {\sqrt {8\sin \left( {s + \pi /6} \right)} - 2} \right){\text{ }} \cr
& {\text{find }}\frac{{dw}}{{ds}}{\text{ }} \cr
& \frac{{dw}}{{ds}} = \frac{d}{{ds}}\left( {\sin \left( {\sqrt {8\sin \left( {s + \pi /6} \right)} - 2} \right){\text{ }}} \right) \cr
& \frac{{dw}}{{ds}} = \cos \left( {\sin \left( {\sqrt {8\sin \left( {s + \pi /6} \right)} - 2} \right){\text{ }}} \right)\frac{d}{{ds}}\left( {\sqrt {8\sin \left( {s + \pi /6} \right)} - 2} \right) \cr
& {\text{find the derivative}} \cr
& \frac{{dw}}{{ds}} = 8\cos \left( {\sin \left( {\sqrt {8\sin \left( {s + \pi /6} \right)} - 2} \right){\text{ }}} \right)\left( {\frac{{\cos \left( {s + \pi /6} \right)}}{{2\sqrt {8\sin \left( {s + \pi /6} \right)} }}} \right) \cr
& \cr
& {\text{Evaluate at }}s = 0 \cr
& {\left. {\frac{{dw}}{{ds}}} \right|_{s = 0}} =8 \cos \left( {\sin \left( {\sqrt {8\sin \left( {\pi /6} \right)} - 2} \right){\text{ }}} \right)\left( {\frac{{\cos \left( {\pi /6} \right)}}{{2\sqrt {8\sin \left( {\pi /6} \right)} }}} \right) \cr
& {\left. {\frac{{dw}}{{ds}}} \right|_{s = 0}} = 8\cos \left( {\sin \left( {\sqrt 4 - 2} \right){\text{ }}} \right)\left( {\frac{{\sqrt 3 /2}}{{2\sqrt 4 }}} \right) \cr
& {\left. {\frac{{dw}}{{ds}}} \right|_{s = 0}} = 8\cos \left( {\sin \left( 0 \right){\text{ }}} \right)\left( {\frac{{\sqrt 3 }}{8}} \right) \cr
& {\left. {\frac{{dw}}{{ds}}} \right|_{s = 0}} = \sqrt 3 \cr} $$
