Answer
$y'=3(2x+1)^{1/2}$
Work Step by Step
Rewrite the equation: $y=(2x+1)(2x+1)^{1/2}=(2x+1)^{3/2}$
Take the derivative of the equation using Power Rule, and Chain Rule:
$y'=\frac{3}{2}(2x+1)^{1/2}\times(2+0)=3(2x+1)^{1/2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Practice Exercises - Page 178: 37
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