Answer
$\approx16.086$
Work Step by Step
by Fubini's Theorem
$\int^{1}_{0} \int^{3}_{0}xe^{xy}dx dy$
=$\int^{3}_{0} \int^{1}_{0} xe^{xy} dy dx$
=$\int^{3}_{0} (e^xy]^{y=1}_{t=0}]dx$
=$\int^{3}_{0}(e^x-x)dx$
=$(e^x-x)]^3_0$
=$e^3-4\approx16.086$
