Answer
4
Work Step by Step
V=$\int\int f(x,y)dA$
=$\int^{4}_{0} \int^{2}_{0}\frac{y}{2}dy dx$
=$\int^{4}_{0}[\frac{y^2}{4}]^2_0dx$
=$\int^{4}_{0}1dx$
=$[x]^4_0$
=4
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.1 - Double and Iterated Integrals over Rectangles - Exercises 15.1 - Page 875: 28
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