Answer
$(ln2)^2$
Work Step by Step
$\int^{2}_{1}\int^{2}_{1}\frac{1}{xy}dy$ dx
=$\int^{2}_{1}\frac{1}{x}(ln2 -ln 1)dx$
=$(ln2)\int^{2}_{1}\frac{1}{x}dx$
=$(ln2)^2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.1 - Double and Iterated Integrals over Rectangles - Exercises 15.1 - Page 875: 23
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