Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.1 - Three-Dimensional Coordinate Systems - Exercises 12.1 - Page 696: 59

Answer

a )$\sqrt{y^2+z^2}$; b) $\sqrt{x^2+z^2}$ c) $\sqrt{x^2+y^2}$

Work Step by Step

a) The distance between two points is: $\sqrt{(x-x_0)^2+(y-y_0)^2+(z-z_0)^2}$ Need to find the distance from point $P(x,y,z)$ to the x-axis or $(x,0,0)$. $\sqrt{(x-x)^2+(y-0)^2+(z-0)^2}=\sqrt{y^2+z^2}$ b) The distance between two points is: $\sqrt{(x-x_0)^2+(y-y_0)^2+(z-z_0)^2}$ Need to find the distance from point $P(x,y,z)$ to the y-axis or, $(0,y,0)$. $\sqrt{(x-0)^2+(y-y)^2+(z-0)^2}=\sqrt{x^2+z^2}$ c) The distance between two points is: $\sqrt{(x-x_0)^2+(y-y_0)^2+(z-z_0)^2}$ Need to find the distance from point $P(x,y,z)$ to the z-axis or $(0,0,z)$. $\sqrt{(x-0)^2+(y-0)^2+(z-z)^2}=\sqrt{x^2+y^2}$
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