Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.1 - Three-Dimensional Coordinate Systems - Exercises 12.1 - Page 696: 28

Answer

(a) $x^2+y^2=4^2 , z=0$ (b) $y^2+z^2=4,x=0$ (c) $x^2+z^2=4, y=0$

Work Step by Step

The equations of the circle with radius $r$ and center at origin in the xy-plane is represented as:$x^2+y^2=r^2$ when $z=0$, likewise for $yz-$plane $y^2+z^2=r^2$ when $x=0$ and for $xz-$ plane: $x^2+z^2=r^2$ when $y=0$ Hence, our equations are: (a) $x^2+y^2=4^2 , z=0$ (b) $y^2+z^2=4,x=0$ (c) $x^2+z^2=4, y=0$
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