Answer
The first five terms are $\frac{1}{2}, \frac{1}{6}, \frac{1}{24}, \frac{1}{120}, \frac{1}{720}.$
Work Step by Step
To find the first five terms of $a_n = \frac{1}{(n + 1)!}$, we must plug in $n=1, n=2, n=3, n=4$ and $n=5.$
Hence the first five terms are $\frac{1}{2!}, \frac{1}{3!}, \frac{1}{4!}, \frac{1}{5!}, \frac{1}{6!}$, i.e.
$$\frac{1}{2}, \frac{1}{6}, \frac{1}{24}, \frac{1}{120}, \frac{1}{720}.$$
