Answer
0.4286, 0.4615, 0.4737, 0.4800, 0.4839, 0.4865, 0.4884, 0.4898, 0.4909, 0.4918
$\lim\limits_{n \to \infty}=\frac{1}{2}$
Work Step by Step
Because the highest power of n is 1, we divide both the numerator and denominator by n to the power of 1. This will allow us to end up with $\frac{\frac{3n}{n}}{\frac{1}{n}+\frac{6}{n}}$.
Simplifying it to $\frac{3}{\frac{1}{n}+6}$ will allow us to find the limit of the sequence.
$\lim\limits_{n \to \infty} a_{n}= \frac{1}{2}$
To find the first 10 terms of the sequence, we will plug in values of a from 1 to 10.
