Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 666: 13

Answer

The distance between the two points is $~~2\sqrt{7}$

Work Step by Step

We can find the Cartesian coordinates of the first point: $x_1 = 4~cos~\frac{4\pi}{3} = -2$ $y_1 = 4~sin~\frac{4\pi}{3} = -3.464$ We can find the Cartesian coordinates of the second point: $x_2 = 6~cos~\frac{5\pi}{3} = 3$ $y_2 = 6~sin~\frac{5\pi}{3} = -5.196$ We can find the distance between the two points: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ $d = \sqrt{(3-(-2))^2+(-5.196-(-3.464))^2}$ $d = \sqrt{28}$ $d = 2\sqrt{7}$ The distance between the two points is $~~2\sqrt{7}$
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