Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 67: 39

Answer

$\ln250$

Work Step by Step

$\ln10+2\ln5=\ln10+\ln5^2=\ln(10\times5^2)=\ln250$
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