Answer
$y=\frac{1}{2}\ln x+\frac{1}{2}$
Work Step by Step
$y=e^{2x-1}$
$2x-1=\ln y$
$2x=\ln y +1$
$x=\frac{1}{2}\ln y+\frac{1}{2}$
$y\leftrightharpoons x$
$y=\frac{1}{2}\ln x+\frac{1}{2}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 67: 23
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