Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.5 Derivatives of Trigonometric Functions - 3.5 Exercises - Page 169: 39

Answer

\[\frac{{dy}}{{dz}} = {\cos ^2}z - {\sin ^2}z\]

Work Step by Step

\[\begin{gathered} y = \frac{1}{{\sec z\csc z}} \hfill \\ \hfill \\ rewrite\,\,use\,trigonometric\,identities \hfill \\ \hfill \\ y = \cos z\sin z \hfill \\ \hfill \\ {\text{using}}\,\,the\,\,product\,rule. \hfill \\ \hfill \\ \frac{{dy}}{{dz}} = \cos z\,\left( {\cos z} \right) + \sin z\,\left( { - \sin z} \right) \hfill \\ \hfill \\ simplify \hfill \\ \hfill \\ \frac{{dy}}{{dz}} = {\cos ^2}z - {\sin ^2}z \hfill \\ \hfill \\ \end{gathered} \]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.