Answer
=1
Work Step by Step
\[\begin{gathered}
Evaluate\mathop {\,\,\lim }\limits_{x \to 0} \,\,\,\frac{{\sin \,x}}{x} \hfill \\
\hfill \\
\,set\,\,\,x = 0 \hfill \\
\hfill \\
then \hfill \\
\hfill \\
\sin \,\left( 0 \right) = 0 \hfill \\
x = 0 \hfill \\
\hfill \\
\mathop {\lim }\limits_{x \to 0} \,\,\frac{{\sin x}}{x} = \frac{0}{0} \hfill \\
\hfill \\
indeterminate\,\,\,form \hfill \\
from\,\,the\,\,theorem\,\,7.11 \hfill \\
\hfill \\
\mathop {\lim }\limits_{x \to 0} \,\,\frac{{\sin x}}{x} = 1 \hfill \\
\end{gathered} \]