Answer
\[\frac{{dy}}{{dx}} = \sec x\tan x - \csc x\cot x\]
Work Step by Step
\[\begin{gathered}
y = \sec x + \csc x \hfill \\
\hfill \\
differentiate \hfill \\
\hfill \\
\frac{{dy}}{{dx}} = \frac{d}{{dx}}\,\,\left[ {\sec x} \right] + \frac{d}{{dx}}\,\,\left[ {\csc x} \right] \hfill \\
\hfill \\
then \hfill \\
\hfill \\
\frac{{dy}}{{dx}} = \sec x\tan x - \csc x\cot x \hfill \\
\hfill \\
\end{gathered} \]