Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 16 - Vector Calculus - Review - Exercises - Page 1189: 8

Answer

$$\dfrac{\pi}{4}$$

Work Step by Step

$\int_CF.dr=\int_0^{\pi}(1+t)sintcostdt+\int_0^{\pi}sin^2tdt$ $=[\frac{-1}{2}(1+t)cos2t+\frac{sin2t}{4}]_0^{\pi}+[\frac{t}{2}-\frac{sin2t}{4}]_0^{\pi}$ $=-\dfrac{\pi}{4}+\dfrac{\pi}{2}$ $$\int_CF.dr=\dfrac{\pi}{4}$$
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