Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 16 - Vector Calculus - Review - Exercises - Page 1189: 15

Answer

Green's Theorem has been verified. $$\int_C Pdx+Qdy=\int\int_D(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y})dA=0$$

Work Step by Step

Green's Theorem states that $$\int_C Pdx+Qdy=\int\int_D(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y})dA$$ $$\int_C Pdx+Qdy=\int_{C_1}Pdx+Qdy+\int_{C_2}Pdx+Qdy=0$$ and $$\int\int_D(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y})dA=\int\int_D(-2xy-2xy)=-\int\int_D4xydA$$ $$=\int_{-1}^{1}\int_{x^2}^{1}4xydydx$$ $$\int\int_D(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y})dA=0$$ Green's Theorem has been verified. $$\int_C Pdx+Qdy=\int\int_D(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y})dA=0$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.