Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - Chapter Review Exercises - Page 461: 81

Answer

The integral diverges.

Work Step by Step

We have $$ \int_{0}^{\pi/2} \cot \theta d\theta=\int_{0}^{\pi/2} \frac{\cos \theta}{\sin\theta} d\theta=\int_{0}^{\pi/2} \frac{d\sin\theta}{\sin\theta} \\ =\ln(\sin\theta)|_0^{\pi/2}=\ln 1- \ln 0=-\infty. $$ Hence, the integral diverges.
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