Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - Chapter Review Exercises - Page 461: 73

Answer

a) $0.1587$ b) $\frac{1}{2}$

Work Step by Step

a) $p(X\geq45)$ = $1-p(X\leq45)$ = $1-F(\frac{45-40}{5})$ = $1-F(1)$ $\approx$ $1-0.8413$ $\approx$ $0.1587$ b) $p(0\leq{X}\leq40)$ = $p(X\leq40)$ - $p(X\leq0)$ = $F(\frac{40-40}{5})-F(\frac{0-40}{5})$ = $F(0)-F(-8)$ $\frac{1}{2}-F(-8)$ $\approx$ $\frac{1}{2}-0$ = $\frac{1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.