Answer
$\frac{3}{4}$
Work Step by Step
$P(X\leq1)$ = $\int_{-\infty}^{1}p(x)dx$ = $\frac{1}{\pi}\int_{-\infty}^{1}\frac{1}{x^{2}+1}dx$ = $\frac{1}{\pi}tan^{-1}x|_{-\infty}^{1}$ = $\frac{3}{4}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - Chapter Review Exercises - Page 461: 69
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