Answer
$$\frac{\pi}{6}$$
Work Step by Step
Let $\sec^{-1}\frac{2}{\sqrt 3}=x $, then we have
$$\sec x =\frac{2}{\sqrt 3}\Longrightarrow x=\frac{\pi}{6}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 374: 4
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