Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.7 L'Hôpital's Rule - Exercises - Page 366: 7

Answer

L’Hôpital’s Rule does not apply and the limit is $0$.

Work Step by Step

Since we have $$ \lim _{x \rightarrow 0} \frac{\sin 4x}{x^{2}+3x+1}=\frac{0}{1}=0. $$ then L’Hôpital’s Rule does not apply and the limit is $0$.
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