Answer
$$-\frac{9}{2}$$
Work Step by Step
Since
$$
\lim _{x \rightarrow \infty} \frac{9x +4 }{3-2x}=-\frac{\infty}{\infty}
$$
is an intermediate form, then we can apply L’Hôpital’s Rule as follws
$$
\lim _{x \rightarrow \infty} \frac{9 }{-2}=-\frac{9}{2}.
$$
