Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.5 Work and Energy - Exercises - Page 317: 9

Answer

$-3.8 \ J$

Work Step by Step

The work required to compress the spring beyond equilibrium can be calculated as: $\text{Work}, W= \int_{m}^{n} F(x) \ dx $; where $k$ is the spring constant. We are given that $k=100 \ N/m$ Now, $W= \int_{m}^{n} F(x) \ dx\\= \int_{0}^{0.3} -kx^{1.1} \ dx\\=-(100) [\dfrac{x^{2.1}}{2.1}]_{0}^{0.3} \\=-\dfrac{100}{2.1} \times (0.3)^{2.1} \\=-3.8 \ J$
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