Answer
$W$ = $3.92\times{10}^{6}$
Work Step by Step
volume of one layer of water is $32Δy$ $m^{3}$
force each layer is $(9.8)(1000)(32Δy)$ = $313600Δy$ $N$
$W$ = $\int_0^{5}(313600y)dy$
$W$ = $156800y^{2}|_0^5$
$W$ = $3.92\times{10}^{6}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.5 Work and Energy - Exercises - Page 317: 17
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