Answer
1770
Work Step by Step
\begin{equation}
\sum_{k=1}^{30}(4k-3)=4\sum_{k=1}^{30}k-\sum_{k=1}^{30}3\end{equation}\begin{equation}=4\times\frac{30(30+1)}{2}-(30\times3)=1770\end{equation}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.1 Approximating and Computing Area - Exercises - Page 236: 36
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