Answer
352,800
Work Step by Step
\begin{equation}\sum_{j=1}^{20}8j^{3}=8\sum_{j=1}^{20}j^{3}=8\times\frac{20^{2}(20+1)^{2}}{4}=352,800\end{equation} Formula (5) is used.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.1 Approximating and Computing Area - Exercises - Page 236: 35
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