Answer
$14.4\,ft^{3}/min $
Work Step by Step
$\frac{dV}{dh}=\frac{d}{dh}(18\,ft^{2}\times h)=18\,ft^{2}$
$\frac{dh}{dt}=0.8\,ft/min $
$\frac{dV}{dt}=\frac{dV}{dh}\times \frac{dh}{dt}=18\,ft^{2}\times0.8\,ft/min $
$=14.4\,ft^{3}/min $
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.9 Related Rates - Exercises - Page 159: 2
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