Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 131: 45

Answer

$D(40)$ = $22.5$ $barrels/year$ increase = $-0.5625$ decrease = $+0.5625$

Work Step by Step

$D(40)$ = $\frac{900}{40}$ = $22.5$ $barrels/year$ increase $D'(p)$ = $-\frac{900}{p^{2}}$ $D'(40)$ = $-\frac{900}{40^{2}}$ = $-0.5625$ decrease $-D'(40)$ = $\frac{900}{40^{2}}$ = $+0.5625$
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