Answer
$$\frac{1}{2}$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow \frac{\pi}{3}}\sin^2(\pi\sin^2x )&=\sin^2(\pi\sin^2\frac{\pi}{3} )\\
&=\sin^2(\pi\frac{3}{4})\\
&=\frac{1}{2}.
\end{align*}
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