Chapter 2 - Limits - 2.4 Limits and Continuity - Exercises - Page 68: 76

$$4$$

\begin{align*} \lim _{x \rightarrow 2} \left(\frac{7x+2}{4-x}\right)^{2/3}&= \left(\frac{14+2}{4-2}\right)^{2/3}\\ &= \left(\frac{14+2}{4-2}\right)^{2/3}\\ &=\left(\frac{16}{2}\right)^{2/3}\\ &=2^2\\ &=4. \end{align*}