Answer
$$\frac{1}{3}$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 3}\frac{x+2}{x^2+2x}&=\frac{3+2}{3^2+2(3)}\\
&=\frac{5}{15}\\
&=\frac{1}{3}.
\end{align*}
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