Answer
The function has a discontinuity at $ x=2$. Moreover, the discontinuity is infinite because $\lim\limits_{x \to 2}\frac{x+1}{4x-2}=\infty $ .
Work Step by Step
Since $$4x-2=0 \Longrightarrow x=2$$
then the function has a discontinuity at $ x=2$. Moreover, the discontinuity is infinite because $\lim\limits_{x \to 2}\frac{x+1}{4x-2}=\infty $ .
