Answer
$ f(x)=[\frac{1}{2}x]$, has a jump discontinuity at $ x=2n $ for every integer $ n $,
Work Step by Step
The function $ f(x)=[\frac{1}{2}x]$, has a jump discontinuity at $ x=2n $ for every integer $ n $, since
$$\lim _{x \rightarrow 2n+}[x]=n, \quad \lim _{x \rightarrow 2n-}[x]=n-1.$$
Moreover, $ f(x)=[x]$ is right-continuous because
$$\lim _{x \rightarrow 2n+}[x]=n, \quad f(2n)=n.$$