Answer
$ f_{xv}=0$
Work Step by Step
We first differentiate with respect to $ x $; then we have
$$ f_x=\frac{2x}{3y^2+\ln(2+u^2)}.$$
Then, we compute $ f_{xv}$, which gives directly
$$ f_{xv}=0.$$
Now, we have
$$ f_{uvxyvu}=0.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 782: 64
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