Answer
$$6, \quad 3$$
Work Step by Step
Since $ Q(y,z)=y^2+y\sin z $, then
$$ Q\left(2,\frac{\pi}{2}\right)=2^2+2\sin \frac{\pi}{2}=4+2=6$$
$$ Q\left(-2,\frac{\pi}{6}\right)=(-2)^2-2\sin \frac{\pi}{6}=4-2.\frac{1}{2}=3$$
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