Answer
$$\frac{3}{10}, \quad -\frac{2}{13}.$$
Work Step by Step
Since $ g(x,y)=\frac{y}{x^2+y^2}$, then
$$ g(1,3)=\frac{3}{1+9}=\frac{3}{10}=\frac{3}{10}.$$
$$ g(3,-2)=\frac{-2}{9+4}=-\frac{2}{13}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 15 - Differentiation in Several Variables - 15.1 Functions of Two or More Variables - Exercises - Page 763: 2
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