Answer
$$6,\quad -\frac{1}{6}$$
Work Step by Step
Since $ h(x,y,z)=xyz^{-2}$, then
$$ h(3,8,2)=(3)(8)(2)^{-2}=\frac{24}{4}=6$$
$$ h(3,-2,-6)=(3)(-2)(-6)^{-2}=\frac{-6}{36}=-\frac{1}{6}$$
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