Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.4 The Cross Product - Exercises - Page 676: 7

Answer

$$0$$

Work Step by Step

$$ \left|\begin{array}{rrr}{1} & {2} & {3} \\ {2} & {4} & {6} \\ {-3} & {-4} & {2}\end{array}\right|=\left|\begin{array}{rrr} {4} & {6} \\ {-4} & {2}\end{array}\right|-2\left|\begin{array}{rrr} {2} & {6} \\ {-3} & {2}\end{array}\right|+3\left|\begin{array}{rrr} {2} & {4} \\ {-3} & {-4}\end{array}\right|\\ =(8+24)-2(4+18)+3(-8+12)\\ =32-44+12=0. $$
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