Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.4 The Cross Product - Exercises - Page 676: 5

Answer

$$-8.$$

Work Step by Step

$$ \left|\begin{array}{rrr}{1} & {2} & {1} \\ {4} & {-3} & {0} \\ {1} & {0} & {1}\end{array}\right|=\left|\begin{array}{rrr} {-3} & {0} \\ {0} & {1}\end{array}\right|-2\left|\begin{array}{rrr} {4} & {0} \\ {1} & {1}\end{array}\right|+\left|\begin{array}{rrr}{4} & {-3} \\ {1} & {0} \end{array}\right|\\ =-3-2(4)+3=-3-8+3=-8. $$
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