Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.4 The Cross Product - Exercises - Page 676: 6

Answer

$$-15.$$

Work Step by Step

$$ \left|\begin{array}{rrr}{1} & {0} & {1} \\ {-2} & {0} & {3} \\ {1} & {3} & {-1}\end{array}\right|=\left|\begin{array}{rrr} {0} & {3} \\ {3} & {-1}\end{array}\right|-0+\left|\begin{array}{rrr}{-2} & {0} \\ {1} & {3} \end{array}\right|\\ =-9-6=-15. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.