Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.1 Parametric Equations - Exercises - Page 603: 8

Answer

$$ y =x^2$$

Work Step by Step

Given $$ x=t^{-1},\ \ \ \ y= t^{-2},$$ Since $ t=\dfrac{1}{x}$, then \begin{align*} y&=\frac{1}{t^2}\\ &=\frac{1}{(1/x)^2}\\ &=x^2 \end{align*} i.e. $$ y =x^2$$
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