Answer
$$ y =x^2$$
Work Step by Step
Given $$ x=t^{-1},\ \ \ \ y= t^{-2},$$
Since $ t=\dfrac{1}{x}$, then
\begin{align*}
y&=\frac{1}{t^2}\\
&=\frac{1}{(1/x)^2}\\
&=x^2
\end{align*}
i.e.
$$ y =x^2$$
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