Answer
The solutions:
$c(t)=(4+t,1+2t)$ and $c(t)=(4+3t,1+6t)$
Work Step by Step
Using equation (3), the line through $(4,1)$ of slope 2 is parametrized by
$x=4+r t$, ${}$ ${}$ $y=1+s t$, ${}$ ${}$ $-\infty
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