Answer
$$ y =(1-x)^{-2}$$
Work Step by Step
Given $$ x=1+t^{-1},\ \ \ \ y= t^2$$
Since $ t=\frac{1}{x-1}$, then
\begin{align*}
y&= t^2\\
&= \frac{1}{(x-1)^2}\\
&=(1-x)^{-2}
\end{align*}
i.e.
$$ y =(1-x)^{-2}$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.1 Parametric Equations - Exercises - Page 603: 12
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