Answer
$$f(x)=
=1+2(x-3)+6(x-3)^2+\frac{1}{2}(x-c)^3+..$$
Work Step by Step
The first four terms of the Taylor series of $ f (x)$ centered at $c = 3$ are:
$$f(x)=f(c)+f'(c)(x-c)+f''(c)(x-c)^2/2!+f'''(c)(x-c)^3/3!+...\\
=1+2(x-3)+6(x-3)^2+\frac{1}{2}(x-c)^3+..$$
