Answer
a)$=13$
b)$=-10$
c)$=0$
d)$=30$
Work Step by Step
a)$\int_0^{7}f(x)$=$\int_0^{5}f(x)+\int_5^{7}f(x)$
$=10+3=13$
b)$\int_5^{0}f(x)=-\int_0^{5}f(x)$
$=-10$
c) Any integral of the form $\int_a^{a}f(x)$ has an area of zero, since, for an antiderivative, $F(x)$, clearly $F(a)-F(a)=0$
Therefore $\int_5^{5}f(x)=0$
d) $\int_0^{5}3f(x)$
$=3\int_0^{5}f(x)$
$=3\times10$
$=30$
