Answer
$-12$
Work Step by Step
Given the values in question
$\int ^{4}_{2}xdx=6;$
$\int ^{4}_{2}dx=2$
$$\Rightarrow \int ^{4}_{2}\left( x-9\right) dx=\int ^{4}_{2}xdx-\int ^{4}_{2}9dx=\int ^{4}_{2}xdx-9\int ^{4}_{2}dx=6-9\times 2=-12$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Page 274: 37
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