Answer
1
Work Step by Step
Sketch:
Function: $f(x)=1-|x|,$ bounds: x=$-1$ to x=$1$.
(see below)
We see a triangle, base length 2, height 1,
$A=\displaystyle \frac{\mathfrak{l}}{2}bh=\frac{1}{2}(2)(1)=1$
$A=\displaystyle \int_{-1}^{1}(1-|x|)dx=1$
