Answer
$$\boxed{\textbf{True}}$$
Work Step by Step
Let $g(x) = \int\sin(x^2)dx$
Therefore, $\int_2^2 \sin(x^2)dx=g(2)-g(2)=0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.3 Exercises - Page 276: 68
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