Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.3 Exercises - Page 276: 64

Answer

False.

Work Step by Step

Counterexample Taking $f(x)=x\qquad g(x)=-x,$ see below The area bounded by f(x) is $-0.5.$ The area bounded by g(x) is $-0.5$ The product, RHS=$-0.25=-\displaystyle \frac{1}{4}.$ The area bounded by $f(x)g(x)=-x^{2}$ , LHS, is slightly greater in magnitude,$ -\displaystyle \frac{1}{3}$ . $LHS=-\displaystyle \frac{1}{3},\qquad RHS=-\frac{1}{4}$
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